the reason the x^2 - x^2 = x^2 - x^2 gives a false solution of 1 = 2 is because in one of the first steps, he divided both sides by (x-x). x-x is always zero, so he divided both sides by zero in the problem, just in case you didn't catch that.

The one where 1=2 is wrong because you divide by zero. Witch is possible with limits but you still end up with an inditerminate form, whitch you can use L'Hopital's rule, where you would end up with (2-2)/(1-1) witch still doesn't work. the limit would not exist. no matter what you cant do it.

I'll bring the one with the x² to my math teacher!!

ReplyDeleteS!

find x, love that

ReplyDeletelol xD

ReplyDeleteSupp Bro :D

Cool post bro!

i love those jokes :D

ReplyDeletemy nerdy gf will appreciate these thanks

ReplyDeleteI don't have friends then I guess :(

ReplyDeletelol

ReplyDeleteHehe, I love those math jokes :)

ReplyDeleteto complicate :)))

ReplyDeleteI love these haha! Keep em coming!

ReplyDeleteBe rational - get real omg i lold so hard.

ReplyDeletehaha nice.

ReplyDeleteLoL PIZZA!

ReplyDeletei get math jokes... and i have no friends.... :(

wtf was the sencond from the bottom i dont get it >.> less its 1=2 is the joke cause 1=1 >.>lol? the find x one worked for me /nod

ReplyDeletelold a lot, thanks!

ReplyDeletehaha, I like those!

ReplyDeleteThe x^2 one...

ReplyDeleteAw snap math jokes up in this joint.

ReplyDeleteNice blog, check mine out.

http://everythingilikesucks.blogspot.com/

mmmmm.... pi.....

ReplyDeleteDaily love

ReplyDeleteIt's old. I've seen these maaany times. The only one that's funny is about i and pi.

ReplyDeletex^2 + x^2 = x^2 + x^2

ReplyDeletex(x - x) = (x + x)(x - x)

x = 2x

1 = 2 ?'

Shockamerica@yahoo.com.vn

the reason the x^2 - x^2 = x^2 - x^2 gives a false solution of 1 = 2 is because in one of the first steps, he divided both sides by (x-x). x-x is always zero, so he divided both sides by zero in the problem, just in case you didn't catch that.

ReplyDeleteThe one where 1=2 is wrong because you divide by zero. Witch is possible with limits but you still end up with an inditerminate form, whitch you can use L'Hopital's rule, where you would end up with (2-2)/(1-1) witch still doesn't work. the limit would not exist. no matter what you cant do it.

ReplyDeletethe x^2 one is wrong. you can't divide by 0.

ReplyDeletethats how uncertain mathematics is....

ReplyDelete